Mathematics — Std 12
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Line and Plane

Ch. 7Std 12

Easy Overview

We just learned how to describe lines in 3D. Now let's add planes into the mix. Planes are flat surfaces that extend infinitely — think of a tabletop, a wall, or the surface of water. And when lines and planes interact, we get interesting questions: where does a line pierce through a plane? What's the angle between a line and a plane? How far is a point from a plane? What about the line where two planes intersect? This chapter answers all of these questions and more. It's the geometry of how things meet in 3D space, and it's used in everything from architectural design to computer graphics to calculating satellite orbits. We start with the equation of a plane. The simplest form is the vector equation: r·n = d, where n is a vector perpendicular to the plane (the normal vector) and d is a constant. In Cartesian form, this becomes ax + by + cz = d, where the coefficients (a, b, c) are the components of the normal vector. If d = 0, the plane passes through the origin. There's also the normal form: r·n̂ = p, where n̂ is a unit normal and p is the perpendicular distance from the origin to the plane. And the intercept form: x/a + y/b + z/c = 1, where a, b, c are the x, y, z intercepts respectively. Each form is useful in different situations. Next, we learn how to find the equation of a plane under different conditions. A unique plane is determined by: (i) a point and a normal vector, (ii) three non-collinear points, (iii) a line and a point not on the line, or (iv) two intersecting lines. For three points, find two vectors in the plane, take their cross product to get the normal, then plug a point into r·n = d. For a line and a point, take the direction of the line and the vector from a point on the line to the given point, cross them to get the normal. Then we tackle angles. The angle between two planes is simply the angle between their normal vectors: cos θ = |n₁·n₂| / (|n₁||n₂|). If n₁·n₂ = 0, the planes are perpendicular. If n₁ and n₂ are parallel, the planes are parallel. For the angle between a line and a plane, we take the complement of the angle between the line and the normal: sin φ = |b·n| / (|b||n|), where b is the line's direction and n is the plane's normal. The distance of a point from a plane has a clean formula: d = |ax₁ + by₁ + cz₁ − d| / √(a² + b² + c²). This is the perpendicular distance — plug the point into the plane equation, take absolute value, divide by the normal vector's magnitude. For two parallel planes, the distance between them is the difference of their d-values divided by the normal magnitude. We also cover the intersection of two planes. Two non-parallel planes always intersect in a straight line. The direction of this line is n₁ × n₂ (perpendicular to both normals). To find a point on the line, set one variable (like z) to 0 and solve the two plane equations. Once you have a point and a direction, you have the line. Finally, we look at coplanarity of lines — whether two lines lie in the same plane. Two lines are coplanar if the scalar triple product (a₂ − a₁)·(b₁ × b₂) = 0, where a₁, a₂ are points on the lines and b₁, b₂ are their directions. If this is zero, they either intersect or are parallel — both are coplanar. If non-zero, they're skew (covered in the 3D geometry chapter). By the end of this chapter, you'll be able to write plane equations from any given data, find intersections and angles involving planes, and solve problems that combine lines and planes in 3D space.

Equation of a Plane — Normal Form

The vector form of a plane is r·n = d, where n is the normal vector (perpendicular to the plane) and d is a constant. The Cartesian form is ax + by + cz = d, where n = (a, b, c). The normal form is r·n̂ = p, where n̂ is a unit normal and p is the perpendicular distance from the origin to the plane. If d > 0, the origin is on the opposite side of the plane from the direction of n.

Equation of a Plane — Intercept Form

If a plane cuts the X-axis at a, Y-axis at b, and Z-axis at c (where a, b, c are the intercepts), the equation is x/a + y/b + z/c = 1. This is called the intercept form. It's the fastest way to write a plane equation if you know where it meets each axis. The intercepts can be positive or negative depending on which side of the origin the plane lies on.

Plane Through a Given Point with Given Normal

If a plane passes through point A with position vector a and has normal vector n, its equation is (r − a)·n = 0, or r·n = a·n. In Cartesian: a(x − x₁) + b(y − y₁) + c(z − z₁) = 0, where (x₁, y₁, z₁) is the point and (a, b, c) is the normal. This expands to ax + by + cz = ax₁ + by₁ + cz₁.

Plane Through Three Non-Collinear Points

Three non-collinear points P, Q, R determine a unique plane. Find two vectors in the plane: PQ = q − p and PR = r − p. The normal is n = PQ × PR (cross product). Then the equation is (r − p)·n = 0. In determinant form: |x−x₁ y−y₁ z−z₁; x₂−x₁ y₂−y₁ z₂−z₁; x₃−x₁ y₃−y₁ z₃−z₁| = 0. This determinant condition is equivalent to the scalar triple product being zero.

Plane Through a Line and a Point

Given a line r = a₁ + λb and a point A (not on the line), the plane containing them has normal n = b × (a − a₁) (the cross product of the line's direction and the vector from a point on the line to A). Then the plane equation is (r − a₁)·n = 0 or (r − a)·n = 0. This works because the plane must contain both the line's direction and the point.

Plane Through Two Intersecting Lines

If two lines intersect (share a common point), the plane containing them has normal n = b₁ × b₂ (cross product of their direction vectors). Then use any point common to both lines (the intersection point) to complete the equation: (r − a)·n = 0, where a is the intersection point. If the lines don't intersect but are parallel, they still determine a plane (the normal is b × (a₂ − a₁)).

Angle Between Two Planes

The acute angle θ between two planes equals the angle between their normal vectors. If plane 1 has normal n₁ and plane 2 has normal n₂: cos θ = |n₁·n₂| / (|n₁||n₂|). Planes are perpendicular if n₁·n₂ = 0. Planes are parallel if n₁ is parallel to n₂ (i.e., n₁ = kn₂). Planes are coincident if they're parallel and have the same d value (same equation or multiples).

Parallel and Perpendicular Planes — Conditions

Two planes a₁x + b₁y + c₁z = d₁ and a₂x + b₂y + c₂z = d₂ are parallel if (a₁, b₁, c₁) is proportional to (a₂, b₂, c₂). They're perpendicular if a₁a₂ + b₁b₂ + c₁c₂ = 0. If they're parallel with d₁ = kd₂ (same proportionality constant as the normals), they're coincident — essentially the same plane. If d₁ ≠ kd₂, they're distinct parallel planes.

Angle Between a Line and a Plane

If a line with direction vector b intersects a plane with normal n, the angle φ between them is the complement of the angle between b and n. Formula: sin φ = |b·n| / (|b||n|). Why sine? Because when the line is parallel to the plane (b ⟂ n, so b·n = 0), the angle is 0° (sin 0 = 0). When the line is perpendicular to the plane (b ∥ n), the angle is 90° (sin 90° = 1).

Distance of a Point from a Plane

The perpendicular distance from point P(x₁, y₁, z₁) to the plane ax + by + cz = d is: distance = |ax₁ + by₁ + cz₁ − d| / √(a² + b² + c²). The numerator is plugging the point into the plane equation and taking absolute value. The denominator is the magnitude of the normal. If the point is on the plane, the numerator is 0. This is one of the handiest formulas in the chapter.

Distance Between Two Parallel Planes

For two parallel planes ax + by + cz = d₁ and ax + by + cz = d₂ (same normal coefficients), the distance between them is: d = |d₁ − d₂| / √(a² + b² + c²). This is just the difference in the constants divided by the normal magnitude. If the normals are proportional but not identical, first multiply one equation to make the normals equal, then apply the formula.

Line of Intersection of Two Planes

Two non-parallel planes intersect in a straight line. The direction of this line is perpendicular to both normals: b = n₁ × n₂. To find a point on the line, set one coordinate (say z = 0) and solve the two plane equations for x and y. Then the line is r = (x₀, y₀, 0) + λ(n₁ × n₂). If setting z = 0 doesn't work (planes parallel to z-axis), try setting x = 0 or y = 0.

Coplanarity of Two Lines

Two lines r = a₁ + λb₁ and r = a₂ + μb₂ are coplanar (lie in the same plane) if and only if (a₂ − a₁)·(b₁ × b₂) = 0. This is the scalar triple product condition. If zero, the lines either intersect or are parallel — both cases are coplanar. If non-zero, the lines are skew (not coplanar). This condition is the 3D equivalent of having two lines in the same plane in 2D.

Foot of the Perpendicular from a Point to a Plane

To find the foot of the perpendicular from a point A(x₁, y₁, z₁) to the plane ax + by + cz = d: the line through A perpendicular to the plane has direction (a, b, c). Write the line parametically: (x₁ + aλ, y₁ + bλ, z₁ + cλ). Substitute into the plane equation to find λ. Then plug λ back to get the foot coordinates. The distance is then |λ|√(a²+b²+c²).

Image of a Point in a Plane

The image of point A in (reflection across) a plane is the point A' such that the plane is the perpendicular bisector of AA'. Find the foot M of the perpendicular from A to the plane. Then A' = 2M − A (vector form). In coordinates: if M is the midpoint of AA', then the image coordinates are (2xₘ − x₁, 2yₘ − y₁, 2zₘ − z₁). This is useful in optics and geometry problems.

Key Points

  • Plane (vector): r·n = d; Plane (Cartesian): ax + by + cz = d — (a,b,c) is the normal
  • Intercept form: x/a + y/b + z/c = 1 — a, b, c are axis intercepts
  • Plane through point with normal n: (r − a)·n = 0
  • Plane through three points: PQ × PR gives the normal
  • Angle between two planes = angle between normals: cos θ = |n₁·n₂| / (|n₁||n₂|)
  • Planes are parallel if normals are proportional; perpendicular if n₁·n₂ = 0
  • Angle between line and plane: sin φ = |b·n| / (|b||n|)
  • Distance from point to plane: d = |ax₁ + by₁ + cz₁ − d| / √(a² + b² + c²)
  • Distance between parallel planes: d = |d₁ − d₂| / √(a² + b² + c²)
  • Intersection of two planes: direction b = n₁ × n₂; find a point by setting one variable to 0
  • Two lines are coplanar if (a₂ − a₁)·(b₁ × b₂) = 0
  • Foot of perpendicular: write line through point along normal, substitute into plane
  • Image of point in plane: find foot M, then A' = 2M − A
  • A plane is uniquely determined by: 3 points, or 1 point + 1 normal, or 1 line + 1 point, or 2 intersecting lines

Practice Questions

  • Find the equation of the plane passing through (1, 2, 3) and perpendicular to the line with direction ratios (2, −1, 3).
  • Find the angle between the planes 2x + 3y − z = 5 and x − 2y + 3z = 7.
  • Find the distance of the point (1, −2, 3) from the plane 2x − 3y + 6z = 14.
  • Find the equation of the line of intersection of the planes x + y + z = 1 and 2x − y + 3z = 4.
  • Find the angle between the line (x−1)/2 = (y+2)/3 = (z−3)/4 and the plane 3x + 4y − 5z = 7.
  • Find the distance between the parallel planes 2x + 3y − z = 5 and 2x + 3y − z = 12.
  • Show that the lines (x−1)/2 = (y−2)/3 = (z−3)/4 and (x−4)/5 = (y−1)/2 = z/1 are coplanar.
  • Find the image of the point (1, 2, 3) in the plane x + 2y + 3z = 10.