Physics — Std 12

Kinetic Theory of Gases and Radiation

Ch. 3Std 12

Easy Overview

Have you ever wondered what is actually happening inside a gas? When you pump air into a bicycle tyre, the pressure increases. When you heat a sealed container, the pressure also increases. But what is pressure, really, at the microscopic level? The kinetic theory of gases answers this beautifully: it connects the macroscopic world of pressure, temperature, and volume that we can measure with instruments to the microscopic world of countless molecules zipping around in constant, random motion. It is one of the greatest intellectual achievements of physics — a bridge between the visible and the invisible. The fundamental picture is this: a gas consists of an enormous number of molecules (about 2.7 × 10²⁵ molecules per cubic metre at room temperature and pressure) moving in all directions with a wide range of speeds. These molecules collide with each other and with the walls of the container. Each collision with a wall exerts a tiny force. Add up the forces from billions upon billions of collisions every second, and you get the macroscopic pressure we measure. The kinetic theory makes several simplifying assumptions: gas molecules are treated as point particles (their size is negligible compared to the distances between them); there are no intermolecular forces except during collisions; collisions are perfectly elastic (no kinetic energy is lost on average); and the motion is completely random. From these assumptions, we can derive the ideal gas equation PV = nRT, which was originally discovered experimentally. The derivation is elegant and illuminating. Consider a cubical container of side length L containing N molecules of a gas, each of mass m. A molecule moving with velocity v_x towards one wall collides, reverses its x-component of velocity, and undergoes a change in momentum of 2mv_x. The time between successive collisions with the same wall is 2L/v_x, so the force exerted by this molecule on the wall is Δp/Δt = (2mv_x)/(2L/v_x) = mv_x²/L. Summing over all N molecules and dividing by the area of the wall (L²), we get pressure P = (Nmv²_rms)/(3V). Since the average kinetic energy per molecule is (½)mv²_rms = (3/2)kT, we arrive at PV = NkT = nRT. The temperature T is nothing but a measure of the average kinetic energy of the molecules — higher temperature means faster-moving molecules. This microscopic picture explains so much. It tells us why the pressure of a gas increases when you compress it (molecules hit the walls more frequently because they travel shorter distances between walls). It explains why heating a gas increases pressure (molecules move faster, hitting walls harder and more often). It predicts Graham's law of effusion (lighter molecules escape faster through a tiny hole). It gives us the Maxwell-Boltzmann distribution of molecular speeds, showing that not all molecules move at the same speed — some are slow, some are fast, and the distribution depends on temperature. It even explains transport phenomena like viscosity, thermal conductivity, and diffusion in gases. For real gases at high pressures or low temperatures, the assumptions break down, and we need corrections — leading to the van der Waals equation. But as a first approximation, the kinetic theory is remarkably powerful and forms the foundation of our understanding of gases.

Assumptions of Kinetic Theory of Gases

The kinetic theory of gases rests on several fundamental assumptions. (1) A gas consists of a large number of molecules that are identical for a given gas. (2) The molecules are in constant, random motion, moving in straight lines until they collide. (3) The size of the molecules is negligible compared to the average distance between them — they are treated as point particles. (4) There are no intermolecular forces except during collisions. (5) All collisions (molecule-molecule and molecule-wall) are perfectly elastic — total kinetic energy is conserved. (6) The duration of a collision is negligible compared to the time between collisions. (7) Newton's laws of motion apply to individual molecules. These assumptions work well for real gases at moderate pressures and temperatures, but break down near the liquefaction point.

Pressure from a Molecular Perspective

Pressure is the result of countless molecular collisions with the container walls. Consider N molecules in a cubical box of side L. A molecule with velocity component v_x towards a wall undergoes a momentum change of 2mv_x when it hits and rebounds. It hits the same wall every 2L/v_x seconds, so the force from this molecule is F = (2mv_x)/(2L/v_x) = mv_x²/L. Summing over all molecules and all three dimensions, the total force on one wall is Σ(mv_x²)/L = (Nm/3)(v²_avg)/L. Pressure = F/L² = (Nm/3)(v²_avg)/L³ = (1/3)(Nmv²_rms)/V. This gives P = (1/3)ρ v²_rms, where ρ is density. This derivation links the macroscopic pressure directly to the microscopic motion of molecules.

The Ideal Gas Equation from Kinetic Theory

From P = (1/3)(Nmv²_rms)/V and the definition of kinetic energy, we can write PV = (2/3)N(½mv²_rms) = (2/3)N⟨KE⟩, where ⟨KE⟩ is the average translational kinetic energy per molecule. Experimental observations show that PV/T is constant for a given amount of gas, so ⟨KE⟩ must be proportional to T. Defining the constant of proportionality as (3/2)k, where k is Boltzmann's constant (1.38 × 10⁻²³ J/K), we get ⟨KE⟩ = (3/2)kT and PV = NkT. Since N = nN_A (where N_A is Avogadro's number) and R = kN_A (gas constant = 8.314 J/mol·K), we obtain the familiar PV = nRT.

Temperature and Molecular Kinetic Energy

The kinetic theory reveals that temperature is a direct measure of the average translational kinetic energy of molecules: (1/2)mv²_rms = (3/2)kT. This means at a given temperature, all gases have the same average molecular kinetic energy regardless of their molecular mass. At 300 K, the average KE per molecule is about 6.2 × 10⁻²¹ J (or about 0.039 eV). The root-mean-square speed v_rms = √(3RT/M) depends on the molar mass — lighter molecules move faster. At the same temperature, hydrogen molecules move about 4 times faster than oxygen molecules (√(32/2) = 4).

Maxwell-Boltzmann Speed Distribution

Not all molecules in a gas move at the same speed. The Maxwell-Boltzmann distribution describes the probability distribution of molecular speeds at a given temperature. The distribution function f(v) = 4πN(m/(2πkT))^(3/2) v² exp(-mv²/(2kT)) gives the number of molecules with speed between v and v+dv. Three characteristic speeds: most probable speed v_p = √(2kT/m) = √(2RT/M); average speed v_avg = √(8kT/πm) = √(8RT/πM); rms speed v_rms = √(3kT/m) = √(3RT/M). These satisfy v_p : v_avg : v_rms = 1 : 1.128 : 1.225.

Degrees of Freedom

A degree of freedom is an independent way in which a molecule can store energy. For a monatomic gas (He, Ne, Ar), there are 3 translational degrees of freedom. For a diatomic gas (H₂, O₂, N₂), there are 3 translational, 2 rotational (about two perpendicular axes), and at high temperatures, 2 vibrational degrees of freedom. At room temperature, diatomic molecules typically have f = 5 (3 translational + 2 rotational) — the vibrational modes are frozen out because the vibrational quantum is too large to be excited at ordinary temperatures. For polyatomic gases, f can be 6 or more.

Law of Equipartition of Energy

The equipartition theorem states that each quadratic degree of freedom contributes an average energy of (1/2)kT per molecule (or (1/2)RT per mole). For a monatomic gas with 3 translational degrees of freedom: U = (3/2)NkT = (3/2)nRT. For a diatomic gas at moderate temperatures (5 DOF): U = (5/2)nRT. At high temperatures (7 DOF including vibration): U = (7/2)nRT. The molar specific heats follow directly: C_V = (dU/dT)_V. So for monatomic: C_V = 3R/2, for diatomic at moderate T: C_V = 5R/2, for diatomic at high T: C_V = 7R/2. The ratio γ = C_P/C_V = 1 + 2/f.

Specific Heat Capacities of Gases

The specific heat capacity of a gas depends on whether it is measured at constant volume (C_V) or constant pressure (C_P). At constant volume, all heat added goes into increasing internal energy. At constant pressure, the gas expands while being heated, doing work on the surroundings — so more heat is needed for the same temperature rise. Hence C_P > C_V. The relation C_P - C_V = R (per mole) holds for all ideal gases. From kinetic theory, C_V = fR/2, so C_P = (f+2)R/2, and γ = C_P/C_V = 1 + 2/f. For monatomic gases: C_V = 3R/2, C_P = 5R/2, γ = 1.67. For diatomic gases at room temperature: C_V = 5R/2, C_P = 7R/2, γ = 1.4.

Mean Free Path

The mean free path (λ) is the average distance a molecule travels between successive collisions. For a gas of molecules with diameter d and number density n, λ = 1/(√2 π d² n). Since n = P/(kT), we can also write λ = kT/(√2 π d² P). At STP (P = 1 atm, T = 273 K), for nitrogen with d ≈ 3.7 × 10⁻¹⁰ m, λ ≈ 68 nm — about 200 molecular diameters. The mean free path is inversely proportional to pressure — in a good vacuum (10⁻⁶ atm), λ can be several metres. This explains why vacuum chambers are needed for experiments where particles must travel long distances without collisions.

Molecular Collision Frequency

The collision frequency (Z) is the average number of collisions a molecule undergoes per second. If a molecule moves with average speed v_avg and has mean free path λ, then Z = v_avg/λ. For nitrogen at STP, v_avg ≈ 454 m/s and λ ≈ 68 × 10⁻⁹ m, giving Z ≈ 6.7 × 10⁹ collisions per second. The total number of collisions per unit volume per second is Z_total = (1/√2) π d² v_avg n². The incredibly high collision frequency is why gases reach equilibrium so quickly — any disturbance is rapidly smoothed out by collisions.

Graham's Law of Effusion

Effusion is the escape of gas molecules through a tiny hole into a vacuum. Graham's law states that the rate of effusion is inversely proportional to the square root of the molar mass: rate ∝ 1/√M. This follows directly from kinetic theory — lighter molecules move faster, so they hit the orifice more frequently. Graham's law is used to separate isotopes of uranium in the enrichment process: gaseous UF₆ containing U-235 effuses slightly faster than UF₆ containing U-238, allowing gradual enrichment over many stages.

Real Gases and Van der Waals Equation

Real gases deviate from ideal gas behaviour at high pressures and low temperatures. The deviations occur because: (1) Molecules have finite size — at high pressures, the volume occupied by the molecules themselves becomes significant. (2) Intermolecular attractive forces become important at close distances — they reduce the pressure. The van der Waals equation corrects for both: (P + an²/V²)(V - nb) = nRT. The term an²/V² corrects for intermolecular attractions. The term nb corrects for molecular volume. The constants a and b are experimentally determined for each gas. At low pressures and high temperatures, the correction terms become negligible.

Critical Temperature and Liquefaction of Gases

Below a certain temperature — the critical temperature (T_c) — a gas can be liquefied by applying sufficient pressure. Above T_c, no amount of pressure can liquefy it. The critical temperature is related to the strength of intermolecular forces — gases with strong attractions (like CO₂, T_c = 31°C) have higher critical temperatures. Gases with weak attractions (like He, T_c = -268°C) have very low critical temperatures. The van der Waals equation predicts the critical point: V_c = 3nb, P_c = a/(27b²), T_c = 8a/(27Rb).

Transport Phenomena in Gases

Kinetic theory also explains transport phenomena. (1) Viscosity: transfer of momentum between layers. η = (1/3)ρv_avgλ. Remarkably, η is independent of pressure (at constant temperature). (2) Thermal conductivity: transfer of heat. κ = (1/3)ρv_avgλC_V/m. Also independent of pressure. (3) Diffusion: transfer of mass. D = (1/3)v_avgλ. All three transport coefficients have the same form — (1/3) × (density) × (average speed) × (mean free path) — reflecting their common origin in molecular motion and collisions.

Adiabatic Processes and the Kinetic Theory

In an adiabatic process, no heat enters or leaves the system. For an ideal gas undergoing a reversible adiabatic process, PV^γ = constant, where γ = C_P/C_V. Kinetic theory provides γ based on degrees of freedom: γ = 1 + 2/f. So γ = 5/3 for monatomic, 7/5 for diatomic, and so on. During adiabatic compression, molecules collide with the moving piston and rebound with increased speed — the temperature increases. During adiabatic expansion, the opposite happens. This is why a bicycle pump gets hot when you compress air rapidly.

Key Points

  • Kinetic theory: large number of molecules in random motion with perfectly elastic collisions.
  • Pressure arises from molecular collisions: P = (1/3)(Nmv²_rms)/V = (1/3)ρv²_rms.
  • Temperature measures average molecular KE: (1/2)mv²_rms = (3/2)kT.
  • Ideal gas equation PV = nRT = NkT is derivable from kinetic theory.
  • v_rms = √(3RT/M). Lighter molecules move faster at the same temperature.
  • Maxwell-Boltzmann distribution describes range of molecular speeds.
  • Degrees of freedom: monatomic f=3, diatomic f=5 (at moderate T).
  • Equipartition: each DOF contributes ½kT. U = (f/2)nRT.
  • Molar specific heats: C_V = fR/2, C_P = (f+2)R/2, γ = 1 + 2/f.
  • C_P - C_V = R for all ideal gases.
  • Mean free path λ = 1/(√2πd²n) = kT/(√2πd²P).
  • Collision frequency Z ≈ 7 × 10⁹ s⁻¹ for air at STP.
  • Graham's law: rate of effusion ∝ 1/√M.
  • Van der Waals equation: (P + an²/V²)(V - nb) = nRT.
  • Critical temperature: above it, gas cannot be liquefied.
  • Transport coefficients (η, κ, D) ≈ (1/3)ρv_avgλ. Viscosity independent of pressure.

Practice Questions

  • Derive the expression for pressure exerted by an ideal gas using the kinetic theory of gases.
  • Using kinetic theory, derive the ideal gas equation PV = nRT. Show that average KE = (3/2)kT.
  • Calculate the rms speed of oxygen molecules at 27°C. Molar mass of oxygen = 32 g/mol. What would be the rms speed of hydrogen at the same temperature?
  • State the law of equipartition of energy. Use it to calculate molar specific heats for monatomic, diatomic, and polyatomic gases.
  • What is the Maxwell-Boltzmann distribution of molecular speeds? Explain the significance of most probable, average, and rms speeds.
  • Derive the expression for mean free path of a gas molecule. How does it depend on temperature and pressure?
  • Explain the deviations of real gases from ideal gas behaviour. State the van der Waals equation and explain the significance of a and b.
  • What is the critical temperature of a gas? Using the van der Waals equation, derive expressions for critical constants P_c, V_c, and T_c.